// this is a very simple example of java serialization example
//Serializations: Assume this is my class to be serialized
import java.util.ArrayList;
public class Dish {
private String dishName;
private ArrayList<String> ingredient;
public String getDishName(){
return this.className;
}
public ArrayList<String> getIngredient(){
return this.variableNames;
}
public void setDishName(String dishName){
this.dishName = dishName;
}
public void setIngredient(ArrayList<String> ingredient){
this.ingredient = ingredient;
}
}
// This class will read and write. I
reused the one found here which is awesome.
// Thanks Awesome person who did this
import java.beans.XMLDecoder;
import java.beans.XMLEncoder;
public class Builder {
public static void writeXML(Schema f, String filename) throws Exception{
XMLEncoder encoder =
new XMLEncoder(
new BufferedOutputStream(
new FileOutputStream(filename)));
encoder.writeObject(f);
encoder.close();
}
public static Schema readXML(String filename) throws Exception {
XMLDecoder decoder =
new XMLDecoder(new BufferedInputStream(
new FileInputStream(filename)));
Schema o = (Schema)decoder.readObject();
decoder.close();
return o;
}
}
// This is a class using both
public class Food {
public static void main(String[] args) {
String filename = "/home/...../Dishes.xml";
String name = "Pizza";
ArrayList<String> ingredients= new ArrayList<String>();
vars.add("dough");
vars.add("cheese");
vars.add("sauce");
Schema s = new Schema();
s.setDishName(name);
s.setIngredient(ingredients);
try { Builder.writeXML(s, filename); }
catch (Exception ex){ System.out.println(ex); }
try {
Schema s2 = Builder.readXML(filename);
System.out.println(s2.getDishName());
System.out.println(s2.getIngredient().toString());
} catch (Exception ex){ System.out.println(ex); }
}
}//Food